What is the mass of water vapor taken at a temperature of 100 degrees, if 4.6 MJ of heat was released

What is the mass of water vapor taken at a temperature of 100 degrees, if 4.6 MJ of heat was released during its condensation? (Specific heat of vaporization and condensation 2.3 10 6 J / kg)

Initial data: t (temperature at which water vapor was taken) = 100 ºС; Q (the amount of heat released during condensation of water vapor) = 4.6 MJ = 4.6 * 10 ^ 6 J.

Reference data: according to the condition L (specific heat of condensation of water vapor) = 2.3 * 10 ^ 6 J / kg.

The mass of water vapor can be determined from the formula: Q = L * m, whence m = Q / L.

Let’s calculate: m = 4.6 * 10 ^ 6 / (2.3 * 10 ^ 6) = 4.6 / 2.3 = 2 kg.

Answer: The mass of water vapor is 2 kilograms.