What is the mass of zinc required to react with 22.4 liters of chlorine?

Let’s find the amount of chlorine substance Cl2.

n = V: Vn.

n = 22.4 L: 22.4 L / mol = 1 mol.

Let’s compose the reaction equation, find in what quantitative ratios the substances are.

Zn + Cl2 = ZnCl2.

According to the reaction equation, there is 1 mole of Cl2 per 1 mole of Zn. Substances are in quantitative ratios 1: 1.

n (Zn) = n (Cl2) = 1 mol.

Let us find the mass of Zn by the formula:

m = n × M,

M (Zn) = 65 g / mol.

m = 1 mol × 65 g / mol = 65 g.

Answer: 65 g.