What is the mass of ZnCl2 chloride and how much hydrogen will be released when 32.5 g of zinc react with an acid?

univerkov | January 28, 2021 | education

Given:
m (Zn) = 32.5g
m (ZnCl2) -?
n (H2) -?
Decision:
Zn + 2HCl = ZnCl2 + H2 ↑
m (ZnCl2) = m (Zn) + m (Cl2) = 68g
n (Zn) = 32.5 \ 65 = 0.5 mol
n (H2) = 0/5 mol
Answer: 0.5 mol; 68 gram

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