What is the maximum height of a body thrown vertically upward at a speed of 30m / s. Movement resistance neglected

V0 = 30 m / s.

g = 10 m / s2.

V = 0 m / s.

hmax -?

The body, which is thrown vertically upward, is acted upon only by the gravity force m * g, directed vertically downward. Since the force is directed in the opposite direction of the movement of the body, it will be decelerated with the acceleration of free fall g until it stops completely. The maximum height hmax of the body will be at the moment when the body stops.

Let us express the height of the body lifting h by the formula: h = (V0 ^ 2 – V ^ 2) / 2 * g.

Since hmax, when V = 0 m / s, then hmax = V0 ^ 2/2 * g.

hmax = (30 m / s) ^ 2/2 * 10 m / s2 = 45 m.

Answer: the maximum height of lifting the body is hmax = 45 m.