What is the maximum mass of sodium hydroxide that can be obtained from sodium oxide

What is the maximum mass of sodium hydroxide that can be obtained from sodium oxide by a chemical amount of 0.56 mol.

To solve it, we will compose an equation, indicate the coefficients:
Na2O + H2O = 2NaOH – hydration reaction, sodium hydroxide obtained;
Let’s determine the molar masses of substances:
M (Na2O) = 61.8 g / mol;
M (NaOH) = 39.9 g / mol;
Let’s calculate the number of moles of sodium hydroxide:
0.56 mol (Na2O) – X mol (NaOH);
-1 mol -2 mol hence, X mol (NaOH) = 0.56 * 2/1 = 1.12 mol;
We find the mass of sodium hydroxide by the formula:
m (NaOH) = Y * M = 1.12 * 39.9 = 44.68 g.
Answer: in the course of the reaction, sodium hydroxide with a mass of 44.68 g was obtained.