What is the maximum possible number of equal sharp corners when two lines of the third line intersect?
| February 18, 2021 | education
Answer: the maximum possible number of equal sharp corners is 4.
In order for the number of equal acute angles to be maximized, it is necessary that two straight lines be parallel, which are crossed by the third, without being a perpendicular. Wherein:
1. When the first straight line intersects on one side, one acute angle is formed. In this case, on the other hand, a second acute opposite angle is formed, equal to the first.
2. Exactly the same picture arises when the third secant line crosses the second.
Thus, we have 4 identical sharp corners. There would be 2 times less of them if two straight lines were not parallel.
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