What is the maximum volume of hydrogen that 14 liters of hexadiene can attach -1.3.

Let’s implement the solution:
1. Let us write the equation according to the problem statement:
1 mol 1 mol;
Н2С = С = СН – СН2 – СН2 – СН3 + Н2 = Н3С – СН = СН – СН2 – СН2 – СН3 – hydrogenation reaction of hexadiene – 1.3, hexene was obtained;
2. Let’s calculate the number of moles of the substance С6Н10, Н2:
1 mol of gas at normal level – 22.4 liters;
X mol (C6H10) – 14 liters. hence, X mol (C6H10) = 1 * 14 / 22.4 = 0.625 mol;
Y (H2) = 0.625 mol, since according to the equation, the number of moles of hydrogen and hexadiene is 1 mol.
3. Find the volume of hydrogen:
V (H2) = 0.625 * 22.4 = 14 liters.
Answer: during the reaction, H2 is released with a volume of 14 liters.