What is the middle line of the trapezoid ABCD if BC = 5cm, AD = 7cm?

A trapezoid is a figure in which two opposite sides are parallel. These opposite parallel sides are called bases.

Since there are no other indications in the condition, and the given sides BC and AD are opposite sides of the trapezoid ABCD, they are grounds.

The middle line of a trapezoid is equal to the half-sum of its bases, then for a trapezoid ABCD its middle line is MN = (BC + AD) / 2.

Thus, taking into account BC = 5 cm, AD = 7 cm, the middle line of the trapezoid ABCD is

MN = (5 + 7) / 2 = 12/2 = 6 cm.



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