What is the minimum volume of gasoline that must be burned so that the released amount

| May 15, 2021 | education

What is the minimum volume of gasoline that must be burned so that the released amount of heat is enough to heat water with a mass of m = 1.0 tons per delta t = 10 degrees Celsius

mwater = 1 t = 1000 kg. Δt = 10 “C. C = 4200 J / kg *” C. λ = 4.6 * 10 ^ 7 J / kg.
mben -?
To heat water, you need the amount of heat Qwater, which is determined by the formula: Qwater = C * mwater * Δt, where C is the specific heat capacity of water, mwater is the mass of water, Δt is the change in water temperature. When gasoline is burned, the amount of heat Qben is released, which is determined by the formula: Qben = λ * mben, where λ is the specific heat of combustion of the fuel, mben is the mass of burned gasoline. Qwater = Qben. C * mwater * Δt = λ * mben. mben = C * mwater * Δt / λ. mben = 4200 J / kg * “C * 1000 kg * 10” C / 4.6 * 10 ^ 7 J / kg = 0.91 kg.
Answer: to heat the water, you need to burn mben = 0.91 kg of gasoline.



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