What is the modulus of the resultant forces applied to a body weighing 2 kg if the dependence

| May 7, 2021 | education

What is the modulus of the resultant forces applied to a body weighing 2 kg if the dependence of its coordinates on time has the form x (t) = 4t ^ 2 + 5t-2 and y (t) = 3t ^ 2 + 4t + 14

Task data: m (weight of the specified body) = 2 kg; dependence of coordinates on time: x (t) = 4t ^ 2 + 5t – 2, y (t) = 3t ^ 2 + 4t + 14.

To find the value of the resultant forces applied to the specified body. we use the formula: F = m * a = m * √ (ax ^ 2 + ay ^ 2) = m * √ ((x (t) “) ^ 2 + (y (t) ”) ^ 2).

Let’s perform the calculation: F = m * √ ((x (t) ”) ^ 2 + (y (t) ”) ^ 2) = 2 * √ (((4t ^ 2 + 5t – 2) ”) ^ 2 + ((3t ^ 2 + 4t + 14) ”) ^ 2) = 2 * √ (8 ^ 2 + 6 ^ 2) = 2 * 10 = 20 N.

Answer: The modulus of the resultant forces, according to the calculation, is 20 N.



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