What is the movement of a cyclist in 5 seconds after the start of braking, if his initial speed during braking is 10 m / s

What is the movement of a cyclist in 5 seconds after the start of braking, if his initial speed during braking is 10 m / s, and his acceleration is 1.2 m / s ^ {2}? what is the coordinate of the cyclist at the moment of time t = 5c, if at the initial moment of time he was at the origin of coordinates?

t = 5 s.

V0 = 10 m / s.

a = 1.2 m / s2.

x0 = 0 m.

x -?

S -?

The movement of the cyclist S is a vector that connects its initial and final positions.

Since the cyclist brakes uniformly, his coordinate changes according to the law: x (t) = x0 + V0 * t – a * t ^ 2/2, where x0 is the initial coordinate, V0 is the initial speed, is the acceleration during braking.

For a cyclist, the equation of motion will be: x (t) = 10 * t – 1.2 * t ^ 2/2 = 10 * t – 0.6 * t ^ 2.

x (5 s) = 10 * 5 – 0.6 * (5) ^ 2 = 37.5 m.

We find the movement of the cyclist by the formula: S = x – x0 = 37.5 m.

Answer: the cyclist will have a coordinate x = 37.5 m, his movement will be S = 37.5 m.