What is the movement of a cyclist in 5 seconds after the start of braking, if his initial

What is the movement of a cyclist in 5 seconds after the start of braking, if his initial braking speed is 10 m / s, and the acceleration is 1.2 m / s2?

Initial data: t (duration of deceleration of the cyclist) = 5 s; V0 (initial speed before braking) = 10 m / s; a (cyclist acceleration modulus) = 1.2 m / s2.

The movement of the cyclist during braking is determined by the formula (we take into account that the movement of the cyclist is slow): S = V0 * t – a * t ^ 2/2.

Calculation: S = 10 * 5 – 1.2 * 5 ^ 2/2 = 50 – 15 = 35 m.

Answer: After the start of braking, the cyclist traveled 35 meters.