What is the movement of a cyclist in 5 seconds after the start of braking
| March 10, 2021 | education
What is the movement of a cyclist in 5 seconds after the start of braking, if his initial speed during braking is 10 m / s, and the acceleration is 1.2 m / s?
t = 5 s.
V0 = 10 m / s.
a = 1.2 m / s2.
S -?
The movement of the body during deceleration S is expressed by the formula: S = V0 * t – a * t ^ 2/2, where V0 is the speed of the body at the beginning of deceleration, t is the deceleration time of the body, a is the acceleration during deceleration.
Substitute the data from the condition of the problem: S = 10 m / s * 5 s – 1.2 m / s2 * (5 s) ^ 2/2 = 35 m.
Answer: when braking, the cyclist will move S = 35 m.
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