What is the ordinate of the vertex of the parabola y = -x ^ 2-6x + 2

y = – x² – 6x + 2. (: – 1).

y = x² + 6x – 2.

a = 1.b = 6.c = – 2.

D = b² – 4 • a • c.

D = 6² – 4 • 1 • (- 2) = 36 + 8 = 44.

x = – b ± √ D / 2a. (total sum / difference divided by 2a).

x ‘= – 6 + √ 44/2.

x ‘= – 6 + 2 √ 11/2.

x ” = – 6 – √ 44/2.

x “= – 6 – 2 √ 11/2.

Thus, the ordinates of the parabola are the points – 6 ± 2 √ 11/2.

The abscissa point is found in the same way if the condition is similar.