What is the oscillation period of a spring pendulum if its mass is 200 g and the spring rate is 20 N / m?

univerkov | September 25, 2021 | education

Initial data: m (mass of the load suspended from the pendulum) = 200 g = 0.2 kg; k (coefficient of stiffness of the pendulum spring) = 20 N / m.

The oscillation period of this spring pendulum is determined by the formula: T = 2Π * √ (m / k).

Let’s calculate the oscillation period: T = 2 * 3.14 * √ (0.2 / 20) = 0.628 s.

Answer: The period of oscillation of this spring pendulum is 0.628 s.

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