What is the path of a body moving uniformly accelerated with an initial speed of 30 km / h
| May 20, 2021 | education
What is the path of a body moving uniformly accelerated with an initial speed of 30 km / h and an acceleration of 0.5 m / s2 in a time interval of 10 s?
Initial data: V0 (initial speed of body movement) = 30 km / h; a (acceleration with which the body moved, a = const (uniformly accelerated motion)) = 0.5 m / s ^ 2; t (time interval during which the movement lasted) = 10 s.
SI system: V0 = 30 km / h = 30 * 1000/3600 = 8.33 m / s.
The path that the body will travel can be calculated using the formula: S = V0 * t + 0.5 * a * t ^ 2.
Let’s perform the calculation: S = 8.33 * 10 + 0.5 * 0.5 * 10 ^ 2 = 108.3 m.
Answer: The body will travel a path equal to 108.3 m.
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