What is the path of a freely falling body in 3 seconds? The initial velocity is zero. What speed will the body have after the specified time?
t = 3 s.
g = 10 m / s2.
V0 = 0 m / s.
On a freely falling body, only gravity acts m * g, so it moves with the acceleration of gravity g.
For uniformly accelerated motion of a body, its path S is determined by the formula: S = V0 * t + g * t ^ 2/2, where V0 is the initial velocity of the body, t is the time of motion of the body.
Since the body falls V0 = 0 m / s, then S = g * t ^ 2/2.
S = 10 m / s2 * (3 s) ^ 2/2 = 45 m.
The speed of the body V with uniformly accelerated motion is expressed by the formula: V = V0 + g * t = g * t.
V = 10 m / s2 * 3 s = 30 m / s.
Answer: the body will travel a path S = 45 m and will have a speed V = 30 m / s.
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