What is the percentage of oxygen in Cr2O3 compounds?

1) W (mass fraction) = Ar (molar mass of the element) / Мr (molar mass of the whole compound) * 100%.
2) Мr (Cr2O3) = 16 * 3 + 52 * 2 = 152;
3) Ar (O) = 16 * 3 = 48.
4) W (O) = 48/152 * 100≈ 31.6%
Answer: 31.6%



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.