What is the perimeter of a parallelogram if its heights are 16 and 8 and the area = 192

First, let’s find what the lengths of the sides of a given geometric figure are equal to.

Let us denote the length of the side of this parallelogram, to which the height of length 16 is lowered through x16, and the length of the side of this parallelogram, to which the height of length 8 is lowered through x8.

Since the area of this geometric figure is 192, the following relations take place:

16 * x16 = 192;

8 * x8 = 192.

From the 1st ratio we find:

x16 = 192/16 = 12.

From the 2nd ratio we find:

x8 = 192/8 = 24.

Find the perimeter of this parallelogram:

12 + 24 + 12 + 24 = 36 + 36 = 72.

Answer: 72.