What is the perimeter of a rectangle whose length is 16 meters and the width is 4 times less?

The perimeter p of a rectangle is twice the sum of the length a and the width b of this rectangle. According to the condition of the problem, the length of the rectangle is 16 meters, and the width of the rectangle is 4 times less than the length. Find the width b of the rectangle.
b = a / 4 = 16/4 = 4 meters
Now we can find the perimeter p of the rectangle:
p = 2 * (a + b) = 2 * (16 + 4) = 2 * 20 = 40 meters
Answer: the perimeter of the rectangle is 40 meters