What is the period of natural oscillations in the circuit if the inductance is 2 mH and the capacitance is 4 μF?
| June 19, 2021 | education
To calculate the value of the period of natural oscillations in the specified circuit, we will use the Thomson formula: T = 2 * Π * √ (C * L).
The values of the variables: C is the electrical capacity of the capacitor of the indicated circuit (C = 4 μF = 4 * 10-6 F); L is the inductance of the coil (L = 2 mH = 2 * 10-3 H);
Calculation: T = 2 * Π * √ (C * L) = 2 * 3.14 * √ (4 * 10-6 * 2 * 10-3) = 0.562 * 10-3 s = 0.562 ms.
Answer: The period of natural oscillations in the specified circuit is 0.562 ms.
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