What is the period of oscillation of a 500 g load suspended from a spring with a stiffness factor of 50 N / m?
| August 5, 2021 | education
Task data: m (weight of the load) = 500 g or 0.5 kg; k (coefficient of spring stiffness) = 50 N / m.
The period of oscillation of the load on the spring can be determined by the formula: T = 2Π * √ (m / k).
Let’s make a calculation: T = 2 * 3.14 * √ (0.5 / 50) = 2 * 3.14 * 0.1 = 0.628 s.
Answer: The weight on the spring oscillates with a period of 0.628 s.
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