What is the period of revolution of an electron if it flies out into a magnetic field

What is the period of revolution of an electron if it flies out into a magnetic field with an induction of 40 mT perpendicular to the magnetic lines of force?

To find the period of revolution of the indicated electron, we will use the formula: T = 2 * Π * me / (B * qе).

Constants and variables: me – electron mass (me = 9.11 * 10-31 kg); B – magnetic induction (B = 40 mT = 40 * 10-3 T); qе – electron charge (qе = -1.6 * 10-19 C).

Calculation: T = 2 * Π * me / (B * qе) = 2 * 3.14 * 9.11 * 10-31 / (40 * 10-3 * 1.6 * 10-19) = 0.894 * 10- 9 s ≈ 1 ns.

Answer: The period of rotation of the indicated electron is 1 ns.