What is the potential energy of a stretched spring if it is stretched 6 cm and a force of 80N is applied to hold it?

x = 6 cm = 0.06 m.
F = 80 N.
W -?
The potential energy W of a stretched spring at x, the stiffness coefficient of which is k, is determined by the formula: W = k * x ^ 2/2
We express the spring stiffness k from Hooke’s law: F = k * x.
k = F / x.
The formula for determining the potential energy of a stretched spring W will take the form: W = F * x ^ 2/2 * x = F * x / 2.
W = 80 N * 0.06 m / 2 = 2.4 J.
Answer: a stretched spring has a potential energy of W = 2.4 J.