What is the potential of the electrostatic field at a point located at a distance of 10 cm from a point charge of 1 nC?

Task data: r (distance from the taken point charge) = 10 cm (in SI r = 0.1 m); q (point charge value) = 1 nC (1 * 10 ^ -9 C).

Reference values: ε0 (electrical constant) = 8.85 * 10-12 F / m.

We calculate the potential of the electrostatic field by the formula: φ = q / (4 * Π * ε0 * r).

Let’s calculate: φ = 1 * 10 ^ -9 / (4 * 3.14 * 8.85 * 10 ^ -12 * 0.1) = 89.96 V.

Answer: The potential of the electrostatic field is 89.96 V.