What is the power of the elevator motor if it lifts 2.5 tons of ore in 1 minute from a mine 300 meters deep?

Let’s convert all units to SI:
h = 300m
m = 2500kg
t = 60s.
Let’s remember the formula for power (N):
N = A / t
In this case, the work is equal to the potential energy at the highest point, i.e. A = mgh. Let’s substitute:
N = mgh / t = 2500 * 10 * 300/600 = 12500W



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