What is the power of the elevator motor if it lifts 3 tons of ore from a mine 400 m deep in 1 min?
| May 25, 2021 | education
Data: h (mine depth, change in ore height) = 400 m; m (mass of ore raised) = 3 t = 3 * 10 ^ 3 kg; t (elapsed time) = 1 min = 60 s; g (acceleration due to gravity) ≈ 10 m / s2.
Hoist motor power: N = A / t = m * g * h / t = 3 * 10 ^ 3 * 10 * 400/60 = 200 * 10 ^ 3 W.
Answer: The motor power is 200 kW.
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