What is the power of the elevator motor if it lifts 3 tons of ore from a mine 400 m deep in 1 min?

Given: m = 3000 kg, h = 400 m, t = 60 s. Find N.

Power is determined by the formula N = A / t, where A – work, J; t – time for which the work was done, s.

The work of lifting the load is determined by the formula A = m * g * h, where m is the weight of the load, kg; g – acceleration of gravity, m / s ^ 2 (g = 9.81 m / s ^ 2); h is the height of the load lifting, m.

We consider: A = 3000 * 9.81 * 400 = 11772000 J; N = 11772000/60 = 196200 W = 196.2 kW.

Answer: N = 196.2 kW.



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