What is the power of the engine, which has completed 18 kilojoules of work in 30 s?

Initial data: t (engine running time) = 30 s; A (the amount of work done by the engine) = 18 kJ.

SI system: A = 18 kJ = 18 * 10 ^ 3 J.

The power of the engine will be equal to the ratio of the work he performed to the time of its execution: N = A / t.

Let’s calculate: N = 18 * 10 ^ 3/30 = 600 watts.

Answer: The motor power is 600 W.



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