What is the pressure exerted by a body weighing 600N on an area of 0.5 m³?

univerkov | September 14, 2021 | education

By definition, the pressure p exerted by the force F on the support with area S is:

p = F / S.

Then the pressure exerted by a body weighing in F = 600 N on an area S = 0.5 m ^ 2 will be:

p = 600 N / 0.5 m ^ 2; p = 300 Pa.

Answer: the body exerts a pressure of 300 Pa.

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