What is the pressure exerted by a force of 500N on a support of 0.25 m2?

univerkov | January 9, 2021 | education

By definition, the pressure P exerted by the force F on the support with the area S is determined by the formula P = F / S where F is the applied force, S is the support area. Then we get:
P = 500 / 0.25 = 2000 Pa = 2 KPa.
Let us express the resulting pressure in atmospheres
2000: 1.33 * 10 ^ 5 = 1.5 * 10 ^ -2 = 0.015 atmospheres

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