What is the pressure exerted by a granite column weighing 4.5 tons on the ground? Its base area is 0.5 m2.

The pressure of a granite column on the ground is the ratio of the force with which the mass of the column presses on the ground to the value of the area of the base of the column.
P = F / S, where F is the pressure force (F = Ft = m * g, where m is the mass of the column (m = 4.5 t = 4.5 * 10 ^ 3 kg), g is the acceleration of gravity (g = 10 m / s ^ 2)), S is the area of the base of the column (S = 0.5 m ^ 2).
Let’s calculate the pressure of the granite column on the ground:
P = F / S = m * g / S = (4.5 * 10 ^ 3) * 10 / 0.5 = 90,000 Pa = 90 * 10 ^ 3 Pa = 90 kPa.
Answer: The pressure of the granite column on the ground is 90 kPa.