What is the pressure from the water side of the submarine at a depth of 50m? What is the force of pressure

What is the pressure from the water side of the submarine at a depth of 50m? What is the force of pressure acting on the hatch in the boat if its area is 2m ^ 2? What pressure will the submarine experience at the same depth, taking into account atmospheric pressure? Density of seawater 1030 kg / m ^ 3

h = 50 m.

g = 10 N / kg.

S = 2 m2.

ρ = 1030 kg / m3.

Ratm = 101325 Pa.

Pr -?

R – ?

Fg -?

F -?

Water acts on the surface of the boat by hydrostatic pressure P, the value of which is expressed by the formula: Pg = ρ * g * h.

Pg = 1030 kg / m3 * 10 N / kg * 50 m = 515000 Pa.

The force of action of water on the hatch Fg is found by the formula: Fg = Pr * S, where S is the area of the submarine hatch.

Fg = 515000 Pa * 2 m2 = 1030000 N.

P = Pr + Ratm.

P = 515000 Pa + 101325 Pa = 616325 Pa.

Taking into account the atmospheric pressure Ratm, the force of action of water on the hatch will be F = 616325 Pa * 2 m2 = 1232650 N.

Answer: Pg = 515000 Pa, Fg = 1030000 N, P = 616325 Pa, F = 1232650 N.