What is the pressure of compressed air in a 20 liter cylinder at a temperature of 12 °

What is the pressure of compressed air in a 20 liter cylinder at a temperature of 12 ° c, if the mass of this air is 2 kg?

Data: V (volume of compressed air cylinder) = 20 l (0.02 m3); T (absolute temperature of compressed air) = 285 K (12 ºС); m (air mass) = 2 kg.

Constants: R (universal gas constant) = 8.314 J / (mol * K); by condition we take M (molar mass of air) = 29 g / mol (0.029 kg / mol).

The compressed air pressure is calculated using the Mendeleev-Clapeyron law: P * V = (m / M) * R * T and P = m * R * T / (V * M).

Calculation: P = 2 * 8.314 * 285 / (0.02 * 0.029) = 8 170 655 Pa ≈ 8.17 MPa.



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