What is the pressure of hydrogen with a mass of 2 kg in a 20 liter cylinder at a temperature of 12 degrees Celsius.

Task data: m (mass of hydrogen) = 2 kg; V (volume of hydrogen) = 20 l (20 dm3; 0.02 m3); T (absolute temperature of hydrogen in the cylinder) = 12 ºС (285 K).

Reference values: R (universal gas constant) = 8.31 J / (mol * K); M (molar mass of hydrogen) = 0.002 kg / mol.

We express the hydrogen pressure in the cylinder from the formula (Mendeleev-Clapeyron’s law): P * V = (m / M) * R * T, whence P = m * R * T / (V * M).

Calculation: P = 2 * 8.31 * 285 / (0.02 * 0.002) = 118417500 Pa (≈ 118.4 MPa).



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