What is the pressure of nitrogen if the mean square velocity of its molecules is 500 m / sa, its density is 1.35 kg / m3.

To determine the nitrogen pressure, we use the basic MKT equation: p = (1/3) mo • n • v • v, where p is the gas pressure, mo is the mass of a nitrogen molecule, n is the concentration of particles, and the root-mean-square velocity of gas molecules v = 500 m / s. Since the mass of gas in the vessel is m = ρV; on the other hand, m = N • mo, where N is the number of particles in the vessel, N • mo = ρV, where the density of the substance is ρ = 1.35 kg / cubic meter. m, particle concentration n = N: V; we obtain ρ = n • mo. Then p = (1/3) ρ • v • v. Let us substitute the values ​​of physical quantities from the condition of the problem into the resulting formula and make calculations: p = (1/3) • 1.35 kg / cubic meter. m • 500 m / s • 500 m / s; p = 112500 Pa.
Answer: nitrogen pressure p = 112500 Pa.