What is the pressure of oxygen if the mean square velocity of its molecules is 500 m / s and its density is 1.43 kg / m3?
| July 17, 2021 | education
Problem data: Vav (mean square velocity of oxygen molecules) = 500 m / s.
Reference values: according to the condition ρк (oxygen density) = 1.43 kg / m3.
The oxygen pressure can be determined by the formula: Р = ρк * Vср2 / 3.
Let’s make a calculation: P = ρk * Vav ^ 2/3 = 1.43 * 500 ^ 2/3 = 119167 Pa ≈ 119.2 kPa.
Answer: The oxygen pressure is 119.2 kPa.
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