What is the probability that in a randomly selected phone number the last digit is even

What is the probability that in a randomly selected phone number the last digit is even, and the penultimate one is odd?

1. Let’s find the probability that the last digit in the phone number is even.

Only 10 digits, of which 5 are even digits, the probability is 5: 10 = 1/2

2. Let’s calculate the probability that the penultimate digit is odd.

Only 10 digits, of which 5 are odd digits, the probability is 5: 10 = 1/2

3. The probability of occurrence of two independent events is equal to the product of the probabilities of occurrence of each of the events.

Thus, the probability that in a randomly selected phone number the last digit is even and the penultimate one is odd is 1/2 * 1/2 = 1/4

Answer. 1/4