What is the pulling force of the rope on which a 50kg load is lifted with an acceleration of 4 m / s ^ 2?

Initial data: m (mass of the lifted load) = 50 kg; a (the acceleration with which the load moves) = 4 m / s ^ 2.

Reference values: g (acceleration due to gravity) = 10 m / s ^ 2.

To determine the rope pulling force, we project all the acting forces onto one axis: m * a = T – m * g and T = m * a + m * g = m * (a + g).

Let’s do the calculation:

T = 50 * (4 + 10) = 50 * 14 = 700 N.

Answer: The rope pulling force will be 700 N.