What is the radius of curvature of the trajectory of a proton moving at a speed of 0.1 m / s

What is the radius of curvature of the trajectory of a proton moving at a speed of 0.1 m / s in a magnetic field with an induction of 1.5 T?

To find the radius of curvature of the trajectory of the proton under consideration, we use the formula: R = mp * V / (qp * B).

Constants and variables: mp – proton mass (m = 1.673 * 10 ^ -27 kg); V – speed (V = 0.1C = 3 * 10 ^ 7 m / s); qp is the proton charge (qp = 1.6 * 10 ^ -19 C); B – magnetic induction (B = 1.5 T).

Let’s perform the calculation: R = mp * V / (qp * B) = 1.673 * 10 ^ -27 * 3 * 10 ^ 7 / (1.6 * 10 ^ -19 * 1.5) = 0.21 m.

Answer: The radius of curvature of the trajectory of the proton under consideration is 0.21 m.