What is the radius of the base of a cylinder with a volume of 36π cm3 and a height of 4 cm?

Since the volume of the cylinder is: V = Sb * h, then Sb = V / h = 36 * p / 4 = 9 * p cm2.

We define the radius of the circle at the base through the area of the base of the cylinder.

Sosn = n * R ^ 2.

R2 = Sb / n = 9 * n / n = 9.

R = 3 cm.

Answer: the radius of the circle is 3 cm.



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