What is the recoil velocity of a 4 kg rifle when a 5 g bullet exits it at a speed of 300 m / s?
| August 5, 2021 | education
mр = 4 kg.
mp = 5 g = 0.005 kg.
Vp = 300 m / s.
Vр -?
mр * Vр = mп * Vп – momentum conservation law.
Vр = mp * Vп / mр.
Vр = 0.005 kg * 300 m / 4 kg = 0.375 m / s.
Answer: the recoil speed of the gun is Vp = 0.375 m / s.
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