What is the resistivity of a meter of a wire with a cross-sectional area of 0.4 mm if 150 m of this wire have a resistance of 90 ohms.

These tasks: S (cross-sectional area of the wire) = 0.4 mm2; l (length) = 150 m; R (resistance) = 90 ohms.

We express the electrical resistivity of the wire material from the formula for calculating the resistance: R = ρ * l / S and ρ = R * S / l.

Calculation: ρ = 90 * 0.4 / 150 = 0.24 Ohm * mm2 / m.

Answer: The material of the wire has a specific electrical resistance of 0.24 Ohm * mm2 / m.



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