What is the root-mean-square velocity of molecules of a gas whose molar mass is equal to 83.1 g / mol

What is the root-mean-square velocity of molecules of a gas whose molar mass is equal to 83.1 g / mol, if this gas is at a temperature of 300 Kelvin?

To determine the value of the root-mean-square velocity of the molecules of the indicated gas, it is necessary to use the formula: Vav = √ (3R * T / M).

Constants and variables: R – universal gas constant (R = 8.31 J / (mol * K)); T is the temperature of the specified gas (T = 300 K); M – molar mass (M = 83.1 g / mol = 83.1 * 10-3 kg).

Calculation: Vav = √ (3R * T / M) = √ (3 * 8.31 * 300 / (83.1 * 10-3)) = 300 m / s.

Answer: The root-mean-square velocity of the molecules of the indicated gas is 300 m / s.