# What is the root mean square velocity of nitrogen molecules, if 2.5 kg occupy

What is the root mean square velocity of nitrogen molecules, if 2.5 kg occupy a volume of 3.2 m3, a pressure of 250 kPa is produced.

To calculate the value of the root-mean-square velocity of the molecules of taken nitrogen, we will use the formula: Vav = √ (3P / ρ) = √ (3P * V / m).

Values of variables: Р – pressure produced by nitrogen (Р = 250 kPa = 25 * 10 ^ 4 Pa); V is the volume occupied by nitrogen (V = 3.2 m3); m – mass (m = 2.5 kg).

Calculation: Vav = √ (3P / ρ) = √ (3 * 25 * 10 ^ 4 * 3.2 / 2.5) = 979.8 m / s.

Answer: The root mean square velocity of the taken nitrogen molecules is 979.8 m / s.

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