What is the seawater pressure at the deepest depth in the Pacific Ocean, 11035m?

Given:

ro = 1030 kg / m3 (kilogram per cubic meter) is the density of seawater;

g = 9.8 N / kg (Newton per kilogram) – acceleration of gravity;

h = 11035 meters – the deepest place in the Pacific Ocean.

It is required to determine P (Pascal) – what is the pressure of sea water at the greatest depth.

To determine the water pressure, you must use the following formula:

P = ro * g * h;

P = 1030 * 9.8 * 11035 = 10094 * 11035 = 111387290 Pascal (approximately equal to 111.4 MPa).

Answer: the water pressure in the deepest part of the Pacific Ocean is 111387290 Pascal (approximately equal to 111.4 MPa).