What is the smallest number of lines you need to draw on the plane so that they have three points of intersection?

To solve the problem, let’s write down the basic concepts in geometry:

1) two non-parallel straight lines a and b1c have a single intersection point, point B.

2) two non-parallel straight lines b1c and a1c1 have one intersection point C.

3) two non-parallel lines ac1 and ab, which we considered in 1) point also have one intersection point, point A.

As a result, we have three points of intersection, points A, B, and C, not parallel to straight lines ab, b1c, a1c1, and this is the minimum number of lines required to obtain three points of intersection A, B, and C.

An example of a shape is a triangle – 3 lines and 3 points of intersection.

Answer: for three points of intersection on a plane, you need to draw three non-parallel straight lines.