What is the specific heat of a brick weighing 3 kg, if 135 kJ of heat is released when it cools down by 50 degrees?
| December 1, 2020 | education
From the formula for the amount of heat Q = cm (t2-t1), we derive the specific heat of a brick (s),
С = Q / m * (t2-t1)
Convert 135kJ to J = 135000
Substitute in the formula with = 135000 / (3 * 50) = 900J or 0.9 kJ
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