What is the specific resistance of the material from which the spiral of a heating element with a power of 2200 W

What is the specific resistance of the material from which the spiral of a heating element with a power of 2200 W is made, calculated for a total current of 10 A, the length of the spiral is 48 m, the cross-sectional area is 0.12 mm.

Initial data: N (power of the heating element coil) = 2200 W; I (current strength for which the heating element is designed) = 10 A; l (spiral length) = 48 m; S (cross-sectional area of the spiral) = 0.12 mm2.

1) Resistance of the heating element spiral: P = I ^ 2 * R and R = P / I ^ 2 = 2200/10 ^ 2 = 22 Ohm.

2) Specific resistance of the spiral material: R = ρ * l / S and ρ = R * S / l = 22 * 0.12 / 48 = 0.055 Ohm * mm2 / m (tungsten).

Answer: The specific resistance of the spiral material is 0.055 Ohm * mm2 / m.