What is the static friction force acting on a 70 kg person running on the road if the coefficient of friction is 0.5?
| March 31, 2021 | education
Initial data: m (mass of a running person) = 70 kg; μ (coefficient of friction) = 0.5.
Reference data: g (acceleration due to gravity) = 9.81 m / s2.
The force of friction at rest, which will act on a running person, is determined by the formula: Ftr = μ * N = μ * m * g.
Calculation: Ftr = 0.5 * 70 * 9.81 = 343.35 N.
Answer: The required static friction force is 343.35 N.
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